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Finding a perpendicular line

Lines that are perpendicular intersect each other at a 90º angle. A plus symbol +, for example, is made up of two lines that run perpendicular to one another. The slopes of perpendicular lines are negative reciprocals of one another. For example: if a line has a slope of 2, then a line perpendicular to it would have a slope of 12.
Let's find the equation of a line perpendicular to y=2x+5 that runs through the point (10,3). To do this, we can use either the point-slope or slope-intercept formula.

Slope-intercept form:
The slope-intercept form for the equation of a line is y=mx+b, in which y represents the y-coordinate of a point on the line, x represents the x-coordinate of the same point on the line, m represents the slope of the line, and b represents the y-intercept of the line, the point at which the line intersects the graph's y-axis.
Take the negative reciprocal of the line's slope, 2, to get 12, and plug it in for m; plug the x-coordinate, 10, in for x; plug the y-coordinate, 3, in for y. This gives us 3=1/2(10)+b, which simplifies to b=2. We can then plug the slope (12) and y-intercept (2) into the slope-intercept formula, y=mx+b, to get the equation of the line, y=12x2.

Point-slope form:
The point-slope form for the equation of a line is yy1=m(xx1), in which x and y represent the x and y-coordinates of a point on the line, x1 and y1 represent the x and y-coordinate of another point on the line, and m represents the slope of the line. Take the negative reciprocal of the line's slope, 2, to get 12, and plug it in for m; plug the x-coordinate, 10, in for x1; plug the y-coordinate, 3, in for y1. This gives us the equation of the line in point-slope form, (y-3)=1/2(x-10).
Simplifying this further will give us the equation of the line in slope-intercept form.

Finding a perpendicular line using point slope