解答 - 矩阵核心运算

$$\in v\left(\left[\begin{array}{cc}3& -4\\ -4& -2\end{array}\right]\right)$$

应用行变换或矩阵运算以得到所需结果。

$$\in v\left(\left[\begin{array}{cc}3& -4\\ -4& -2\end{array}\right]\right)$$

应用行变换或矩阵运算以得到所需结果。

$$\in v\left(\left[\begin{array}{cc}3& -4\\ -4& -2\end{array}\right]\right)$$

R1 <-> R2

$$\left[\begin{array}{cccc}-4& -2& 0& 1\\ 3& -4& 1& 0\end{array}\right]$$

R1 <- -1/4R1

$$\left[\begin{array}{cccc}1& 0.5& 0& -0.25\\ 3& -4& 1& 0\end{array}\right]$$

R2 <- R2 - 3R1

$$\left[\begin{array}{cccc}1& 0.5& 0& -0.25\\ 0& -5.5& 1& 0.75\end{array}\right]$$

R2 <- -2/11R2

$$\left[\begin{array}{cccc}1& 0.5& 0& -0.25\\ 0& 1& -0.181818& -0.136364\end{array}\right]$$

R1 <- R1 - 1/2R2

$$\left[\begin{array}{cccc}1& 0& 0.090909& -0.181818\\ 0& 1& -0.181818& -0.136364\end{array}\right]$$

应用行变换或矩阵运算以得到所需结果。

$$\left[\begin{array}{cc}0.090909& -0.181818\\ -0.181818& -0.136364\end{array}\right]$$

以规范形式呈现最终矩阵或标量结果。

$$\left[\begin{array}{cc}0.090909& -0.181818\\ -0.181818& -0.136364\end{array}\right]$$

以规范形式呈现最终矩阵或标量结果。

$$\left[\begin{array}{cc}0.090909& -0.181818\\ -0.181818& -0.136364\end{array}\right]$$

以规范形式呈现最终矩阵或标量结果。