解答 - 老虎代数解答器

$${\left(491\right)}_{10}$$

步骤: $$4·{10}^2$$
+ $$9·{10}^1$$
+ $$1·{10}^0$$ = $$491$$.

$$491$$

步骤: $$4·{10}^2$$
+ $$9·{10}^1$$
+ $$1·{10}^0$$ = $$491$$.

$$491\left(base10\right)$$

$${491}_{10}=1E{B}_{16}$$.

$$\frac{491}{16}$$

$${491}_{10}=1E{B}_{16}$$.

$$491=16\cdot 30+11$$

$${491}_{10}=1E{B}_{16}$$.

$$30=16\cdot 1+14$$

$${491}_{10}=1E{B}_{16}$$.

$$1=16\cdot 0+1$$

$${491}_{10}=1E{B}_{16}$$.

$$1EB$$

$${491}_{10}=1E{B}_{16}$$.

$${\left(1EB\right)}_{16}$$

$${491}_{10}=1E{B}_{16}$$.