解答 - 绝对值方程

$$\left(x+3\right)=x·2+\frac{\left(-1·2\right)}{3}$$

简化运算:

$$\left(x+3\right)=2x+\frac{-2}{3}$$

从两边减去 $$$$:

$$\left(x+3\right)-2x=\left(2x+\frac{-2}{3}\right)-2x$$

收集同类项:

$$\left(x-2x\right)+3=\left(2x+\frac{-2}{3}\right)-2x$$

简化运算:

$$-x+3=\left(2x+\frac{-2}{3}\right)-2x$$

收集同类项:

$$-x+3=\left(2x-2x\right)+\frac{-2}{3}$$

简化运算:

$$-x+3=\frac{-2}{3}$$

从两边减去 $$$$:

$$\left(-x+3\right)-3=\left(\frac{-2}{3}\right)-3$$

简化运算:

$$-x=\left(\frac{-2}{3}\right)-3$$

将整数转换为分数:

$$-x=\frac{-2}{3}+\frac{-9}{3}$$

组合分数:

$$-x=\frac{\left(-2-9\right)}{3}$$

合并分子:

$$-x=\frac{-11}{3}$$

将 $$$$ 乘以两边:

$$-x·-1=\left(\frac{-11}{3}\right)·-1$$

删除乘以负一项:

$$x=\left(\frac{-11}{3}\right)·-1$$

删除乘以负一项:

$$x=\frac{11}{3}$$

$$\left(x+3\right)=2·\left(-x+\frac{1}{3}\right)$$

$$\left(x+3\right)=-x·2+\frac{\left(1·2\right)}{3}$$

收集同类项:

$$\left(x+3\right)=\left(-1·2\right)x+\frac{\left(1·2\right)}{3}$$

系数之间相乘:

$$\left(x+3\right)=-2x+\frac{\left(1·2\right)}{3}$$

简化运算:

$$\left(x+3\right)=-2x+\frac{2}{3}$$

将 $$$$ 加到等式的两边:

$$\left(x+3\right)+2x=\left(-2x+\frac{2}{3}\right)+2x$$

收集同类项:

$$\left(x+2x\right)+3=\left(-2x+\frac{2}{3}\right)+2x$$

简化运算:

$$3x+3=\left(-2x+\frac{2}{3}\right)+2x$$

收集同类项:

$$3x+3=\left(-2x+2x\right)+\frac{2}{3}$$

简化运算:

$$3x+3=\frac{2}{3}$$

从两边减去 $$$$:

$$\left(3x+3\right)-3=\left(\frac{2}{3}\right)-3$$

简化运算:

$$3x=\left(\frac{2}{3}\right)-3$$

将整数转换为分数:

$$3x=\frac{2}{3}+\frac{-9}{3}$$

组合分数:

$$3x=\frac{\left(2-9\right)}{3}$$

合并分子:

$$3x=\frac{-7}{3}$$

两边都除以 :

$$\frac{\left(3x\right)}{3}=\frac{\left(\frac{-7}{3}\right)}{3}$$

简化分数:

$$x=\frac{\left(\frac{-7}{3}\right)}{3}$$

简化运算:

$$x=\frac{-7}{\left(3·3\right)}$$

$$x=\frac{-7}{9}$$