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最终结果步骤术语和主题

15. (0344827586206896551724137931)

15.(0344827586206896551724137931)

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逐步解答

1. 建立长除法

$\frac{436}{29}$

$\frac{436}{29} = 436 \div 29$ .

$\frac{436}{29}$

$\frac{436}{29} = 436 \div 29$ .

$\frac{436}{29}$

$\frac{436}{29} = 436 \div 29$ .

$436 \div 29$

$\frac{436}{29} = 436 \div 29$ .

$436 \div 29$

$\frac{436}{29} = 436 \div 29$ .

2. 识别循环周期

$\frac{436}{29}$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$\frac{436}{29}$

$\frac{10}{29} = d i g i t 0, r e m a \in d e r 10$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$10$

$\frac{100}{29} = d i g i t 3, r e m a \in d e r 13$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$13$

$\frac{130}{29} = d i g i t 4, r e m a \in d e r 14$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$14$

$\frac{140}{29} = d i g i t 4, r e m a \in d e r 24$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$24$

$\frac{240}{29} = d i g i t 8, r e m a \in d e r 8$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$8$

$\frac{80}{29} = d i g i t 2, r e m a \in d e r 22$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$22$

$\frac{220}{29} = d i g i t 7, r e m a \in d e r 17$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$17$

$\frac{170}{29} = d i g i t 5, r e m a \in d e r 25$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$25$

$\frac{250}{29} = d i g i t 8, r e m a \in d e r 18$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$18$

$\frac{180}{29} = d i g i t 6, r e m a \in d e r 6$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$6$

$\frac{60}{29} = d i g i t 2, r e m a \in d e r 2$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$2$

$\frac{20}{29} = d i g i t 0, r e m a \in d e r 20$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$20$

$\frac{200}{29} = d i g i t 6, r e m a \in d e r 26$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$26$

$\frac{260}{29} = d i g i t 8, r e m a \in d e r 28$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$28$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$14$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

$15. (0344827586206896551724137931)$

$1 \to 10 \to 13 \to 14 \to 24 \to 8 \to 22 \to 17$ , $0344827586206896551724137931$ .

3. 写出循环小数

$436 / 29 = 15. (0344827586206896551724137931)$

$15. (0344827586206896551724137931)$

$(0344827586206896551724137931) = 15. (0344827586206896551724137931)$ .

$15. (0344827586206896551724137931)$

$(0344827586206896551724137931) = 15. (0344827586206896551724137931)$ .

$15. (0344827586206896551724137931)$

$(0344827586206896551724137931) = 15. (0344827586206896551724137931)$ .

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