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最终结果步骤术语和主题

1. (230769)

1.(230769)

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逐步解答

1. 建立长除法

$\frac{1872}{1521}$

$\frac{1872}{1521} = 1872 \div 1521$ .

$\frac{1872}{1521}$

$\frac{1872}{1521} = 1872 \div 1521$ .

$\frac{1872}{1521}$

$\frac{1872}{1521} = 1872 \div 1521$ .

$1872 \div 1521$

$\frac{1872}{1521} = 1872 \div 1521$ .

$1872 \div 1521$

$\frac{1872}{1521} = 1872 \div 1521$ .

2. 识别循环周期

$\frac{1872}{1521}$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$\frac{1872}{1521}$

$\frac{3510}{1521} = d i g i t 2, r e m a \in d e r 468$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$468$

$\frac{4680}{1521} = d i g i t 3, r e m a \in d e r 117$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$117$

$\frac{1170}{1521} = d i g i t 0, r e m a \in d e r 1170$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$1170$

$\frac{11700}{1521} = d i g i t 7, r e m a \in d e r 1053$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$1053$

$\frac{10530}{1521} = d i g i t 6, r e m a \in d e r 1404$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$1404$

$\frac{14040}{1521} = d i g i t 9, r e m a \in d e r 351$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$351$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

$1. (230769)$

$351 \to 468 \to 117 \to 1170 \to 1053 \to 1404$ , $230, 769$ .

3. 写出循环小数

$1872 / 1521 = 1. (230769)$

$1. (230769)$

$(230, 769) = 1. (230769)$ .

$1. (230769)$

$(230, 769) = 1. (230769)$ .

$1. (230769)$

$(230, 769) = 1. (230769)$ .

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