解答 - 几何数列

要找到系列的通用形式，将第一项：$$a=610$$ 和公比：$$r=0.9590163934426229$$ 插入几何级数的公式：

$$a_1=610$$

$$a_2=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{2-1}=610\cdot {0.9590163934426229}^1=610\cdot 0.9590163934426229=585$$

$$a_3=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{3-1}=610\cdot {0.9590163934426229}^2=610\cdot 0.9197124428916957=561.0245901639344$$

$$a_4=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{4-1}=610\cdot {0.9590163934426229}^3=610\cdot 0.8820193099862983=538.031779091642$$

$$a_5=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{5-1}=610\cdot {0.9590163934426229}^4=610\cdot 0.8458709776098106=515.9812963419845$$

$$a_6=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{6-1}=610\cdot {0.9590163934426229}^5=610\cdot 0.8112041342651463=494.8345219017392$$

$$a_7=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{7-1}=610\cdot {0.9590163934426229}^6=610\cdot 0.7779580631887058=474.5544185451105$$

$$a_8=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{8-1}=610\cdot {0.9590163934426229}^7=610\cdot 0.7460745360088408=455.10546696539285$$

$$a_9=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{9-1}=610\cdot {0.9590163934426229}^8=610\cdot 0.7154977107625767=436.4536035651718$$

$$a_{10}=a_1·r^{n-1}=610\cdot {0.9590163934426229}^{10-1}=610\cdot {0.9590163934426229}^9=610\cdot 0.6861740340919793=418.5661607961074$$