Giải pháp - Cac phep toan cot loi cua ma tran

$$\in v\left(\left[\begin{array}{cc}4& 3\\ -4& 4\end{array}\right]\right)$$

Ap dung phep bien doi hang hoac phep toan ma tran de tao ket qua duoc yeu cau.

$$\in v\left(\left[\begin{array}{cc}4& 3\\ -4& 4\end{array}\right]\right)$$

Ap dung phep bien doi hang hoac phep toan ma tran de tao ket qua duoc yeu cau.

$$\in v\left(\left[\begin{array}{cc}4& 3\\ -4& 4\end{array}\right]\right)$$

R1 <- 1/4R1

$$\left[\begin{array}{cccc}1& 0.75& 0.25& 0\\ -4& 4& 0& 1\end{array}\right]$$

R2 <- R2 + 4R1

$$\left[\begin{array}{cccc}1& 0.75& 0.25& 0\\ 0& 7& 1& 1\end{array}\right]$$

R2 <- 1/7R2

$$\left[\begin{array}{cccc}1& 0.75& 0.25& 0\\ 0& 1& 0.142857& 0.142857\end{array}\right]$$

R1 <- R1 - 3/4R2

$$\left[\begin{array}{cccc}1& 0& 0.142857& -0.107143\\ 0& 1& 0.142857& 0.142857\end{array}\right]$$

Ap dung phep bien doi hang hoac phep toan ma tran de tao ket qua duoc yeu cau.

$$\left[\begin{array}{cccc}0& 142857& -0& 107143\\ 0& 142857& 0& 142857\end{array}\right]$$

Trinh bay ket qua ma tran hoac vo huong cuoi cung o dang chuan.

$$\left[\begin{array}{cccc}0& 142857& -0& 107143\\ 0& 142857& 0& 142857\end{array}\right]$$

Trinh bay ket qua ma tran hoac vo huong cuoi cung o dang chuan.

$$\left[\begin{array}{cccc}0& 142857& -0& 107143\\ 0& 142857& 0& 142857\end{array}\right]$$

Trinh bay ket qua ma tran hoac vo huong cuoi cung o dang chuan.