Giải pháp - Trình giải toán Tiger Algebra

$${\left(FCF\right)}_{16}$$

Các bước: $$15·{16}^2$$
+ $$12·{16}^1$$
+ $$15·{16}^0$$ = $$4.047$$.

$$15\cdot {16}^2+12\cdot {16}^1+15\cdot {16}^0$$

Các bước: $$15·{16}^2$$
+ $$12·{16}^1$$
+ $$15·{16}^0$$ = $$4.047$$.

$$4047$$

Các bước: $$15·{16}^2$$
+ $$12·{16}^1$$
+ $$15·{16}^0$$ = $$4,047$$.

$$4047\left(base10\right)$$

$${4.047}_{10}={4.047}_{10}$$.

$$\frac{4047}{10}$$

$${4.047}_{10}={4.047}_{10}$$.

$$4047=10\cdot 404+7$$

$${4.047}_{10}={4.047}_{10}$$.

$$404=10\cdot 40+4$$

$${4.047}_{10}={4.047}_{10}$$.

$$40=10\cdot 4+0$$

$${4.047}_{10}={4.047}_{10}$$.

$$4=10\cdot 0+4$$

$${4.047}_{10}={4.047}_{10}$$.

$$4047$$

$${4.047}_{10}={4.047}_{10}$$.

$${\left(4047\right)}_{10}$$

$$4,{047}_{10}=4,{047}_{10}$$.