Giải pháp - Trình giải toán Tiger Algebra

$${\left(EAD\right)}_{16}$$

Các bước: $$14·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$3.757$$.

$$14\cdot {16}^2+10\cdot {16}^1+13\cdot {16}^0$$

Các bước: $$14·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$3.757$$.

$$3757$$

Các bước: $$14·{16}^2$$
+ $$10·{16}^1$$
+ $$13·{16}^0$$ = $$3,757$$.

$$3757\left(base10\right)$$

$${3.757}_{10}={3.757}_{10}$$.

$$\frac{3757}{10}$$

$${3.757}_{10}={3.757}_{10}$$.

$$3757=10\cdot 375+7$$

$${3.757}_{10}={3.757}_{10}$$.

$$375=10\cdot 37+5$$

$${3.757}_{10}={3.757}_{10}$$.

$$37=10\cdot 3+7$$

$${3.757}_{10}={3.757}_{10}$$.

$$3=10\cdot 0+3$$

$${3.757}_{10}={3.757}_{10}$$.

$$3757$$

$${3.757}_{10}={3.757}_{10}$$.

$${\left(3757\right)}_{10}$$

$$3,{757}_{10}=3,{757}_{10}$$.