Giải pháp - Trình giải toán Tiger Algebra

$${\left(EA\right)}_{16}$$

Các bước: $$14·{16}^1$$
+ $$10·{16}^0$$ = $$234$$.

$$14\cdot {16}^1+10\cdot {16}^0$$

Các bước: $$14·{16}^1$$
+ $$10·{16}^0$$ = $$234$$.

$$234$$

Các bước: $$14·{16}^1$$
+ $$10·{16}^0$$ = $$234$$.

$$234\left(base10\right)$$

$${234}_{10}={234}_{10}$$.

$$\frac{234}{10}$$

$${234}_{10}={234}_{10}$$.

$$234=10\cdot 23+4$$

$${234}_{10}={234}_{10}$$.

$$23=10\cdot 2+3$$

$${234}_{10}={234}_{10}$$.

$$2=10\cdot 0+2$$

$${234}_{10}={234}_{10}$$.

$$234$$

$${234}_{10}={234}_{10}$$.

$${\left(234\right)}_{10}$$

$${234}_{10}={234}_{10}$$.