Giải pháp - Trình giải toán Tiger Algebra

$${\left(\forall A\right)}_{16}$$

Các bước: $$10·{16}^2$$
+ $$10·{16}^1$$
+ $$10·{16}^0$$ = $$2.730$$.

$$10\cdot {16}^2+10\cdot {16}^1+10\cdot {16}^0$$

Các bước: $$10·{16}^2$$
+ $$10·{16}^1$$
+ $$10·{16}^0$$ = $$2.730$$.

$$2730$$

Các bước: $$10·{16}^2$$
+ $$10·{16}^1$$
+ $$10·{16}^0$$ = $$2,730$$.

$$2730\left(base10\right)$$

$${2.730}_{10}={2.730}_{10}$$.

$$\frac{2730}{10}$$

$${2.730}_{10}={2.730}_{10}$$.

$$2730=10\cdot 273+0$$

$${2.730}_{10}={2.730}_{10}$$.

$$273=10\cdot 27+3$$

$${2.730}_{10}={2.730}_{10}$$.

$$27=10\cdot 2+7$$

$${2.730}_{10}={2.730}_{10}$$.

$$2=10\cdot 0+2$$

$${2.730}_{10}={2.730}_{10}$$.

$$2730$$

$${2.730}_{10}={2.730}_{10}$$.

$${\left(2730\right)}_{10}$$

$$2,{730}_{10}=2,{730}_{10}$$.