Giải pháp - Trình giải toán Tiger Algebra

$${\left(3E4\right)}_{16}$$

Các bước: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$4·{16}^0$$ = $$996$$.

$$3\cdot {16}^2+14\cdot {16}^1+4\cdot {16}^0$$

Các bước: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$4·{16}^0$$ = $$996$$.

$$996$$

Các bước: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$4·{16}^0$$ = $$996$$.

$$996\left(base10\right)$$

$${996}_{10}={996}_{10}$$.

$$\frac{996}{10}$$

$${996}_{10}={996}_{10}$$.

$$996=10\cdot 99+6$$

$${996}_{10}={996}_{10}$$.

$$99=10\cdot 9+9$$

$${996}_{10}={996}_{10}$$.

$$9=10\cdot 0+9$$

$${996}_{10}={996}_{10}$$.

$$996$$

$${996}_{10}={996}_{10}$$.

$${\left(996\right)}_{10}$$

$${996}_{10}={996}_{10}$$.