Giải pháp - Trình giải toán Tiger Algebra

$${\left(2A6\right)}_{16}$$

Các bước: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$6·{16}^0$$ = $$678$$.

$$2\cdot {16}^2+10\cdot {16}^1+6\cdot {16}^0$$

Các bước: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$6·{16}^0$$ = $$678$$.

$$678$$

Các bước: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$6·{16}^0$$ = $$678$$.

$$678\left(base10\right)$$

$${678}_{10}={678}_{10}$$.

$$\frac{678}{10}$$

$${678}_{10}={678}_{10}$$.

$$678=10\cdot 67+8$$

$${678}_{10}={678}_{10}$$.

$$67=10\cdot 6+7$$

$${678}_{10}={678}_{10}$$.

$$6=10\cdot 0+6$$

$${678}_{10}={678}_{10}$$.

$$678$$

$${678}_{10}={678}_{10}$$.

$${\left(678\right)}_{10}$$

$${678}_{10}={678}_{10}$$.