Giải pháp - Trình giải toán Tiger Algebra

$${\left(2A2\right)}_{16}$$

Các bước: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$2·{16}^0$$ = $$674$$.

$$2\cdot {16}^2+10\cdot {16}^1+2\cdot {16}^0$$

Các bước: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$2·{16}^0$$ = $$674$$.

$$674$$

Các bước: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$2·{16}^0$$ = $$674$$.

$$674\left(base10\right)$$

$${674}_{10}={674}_{10}$$.

$$\frac{674}{10}$$

$${674}_{10}={674}_{10}$$.

$$674=10\cdot 67+4$$

$${674}_{10}={674}_{10}$$.

$$67=10\cdot 6+7$$

$${674}_{10}={674}_{10}$$.

$$6=10\cdot 0+6$$

$${674}_{10}={674}_{10}$$.

$$674$$

$${674}_{10}={674}_{10}$$.

$${\left(674\right)}_{10}$$

$${674}_{10}={674}_{10}$$.