คำตอบ - Trigonometry

The period of trigonometric functions is 360 degrees.

$$\sin \left(1320°\right)=\sin \left(1320-360°\right)$$

Subtracting one integer from another.

$$\sin \left(1320-360°\right)=\sin \left(960°\right)$$

The period of trigonometric functions is 360 degrees.

$$\sin \left(960°\right)=\sin \left(960-360°\right)$$

Subtracting one integer from another.

$$\sin \left(960-360°\right)=\sin \left(600°\right)$$

The period of trigonometric functions is 360 degrees.

$$\sin \left(600°\right)=\sin \left(600-360°\right)$$

Subtracting one integer from another.

$$\sin \left(600-360°\right)=\sin \left(240°\right)$$

Reflecting the number with respect to 360 degrees.

$$\sin \left(240°\right)=\sin \left(360-120°\right)$$

The period of trigonometric functions is 360 degrees.

$$\sin \left(360-120°\right)=\sin \left(360-120-360°\right)$$

Removing or simplifying the same numbers on the top and bottom of a fraction.

$$\sin \left(360-120-360°\right)=\sin \left(-120°\right)$$

Computing the sine of a negative angle.

$$\sin \left(-120°\right)=-\sin \left(120°\right)$$

Reflecting the number with respect to 360 degrees.

$$-\sin \left(120°\right)=-\sin \left(180-60°\right)$$

Reflecting the sine function with respect to 180 degrees.

$$-\sin \left(180-60°\right)=-\sin \left(60°\right)$$

Computing the sine of 60 degrees.

$$-\sin \left(60°\right)=-\frac{\sqrt{3}}{2}$$