పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=923$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.0010834236186348862$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=923$$

$$a_2=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{2-1}=923\cdot {0.0010834236186348862}^1=923\cdot 0.0010834236186348862=1$$

$$a_3=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{3-1}=923\cdot {0.0010834236186348862}^2=923\cdot 1.1738067374159113E-06=0.0010834236186348862$$

$$a_4=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{4-1}=923\cdot {0.0010834236186348862}^3=923\cdot 1.2717299430291563E-09=1.1738067374159113E-06$$

$$a_5=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{5-1}=923\cdot {0.0010834236186348862}^4=923\cdot 1.3778222568029862E-12=1.2717299430291561E-09$$

$$a_6=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{6-1}=923\cdot {0.0010834236186348862}^5=923\cdot 1.4927651753011767E-15=1.3778222568029862E-12$$

$$a_7=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{7-1}=923\cdot {0.0010834236186348862}^6=923\cdot 1.617297047996941E-18=1.4927651753011765E-15$$

$$a_8=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{8-1}=923\cdot {0.0010834236186348862}^7=923\cdot 1.752217820148365E-21=1.617297047996941E-18$$

$$a_9=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{9-1}=923\cdot {0.0010834236186348862}^8=923\cdot 1.898394171341674E-24=1.752217820148365E-21$$

$$a_{10}=a_1·r^{n-1}=923\cdot {0.0010834236186348862}^{10-1}=923\cdot {0.0010834236186348862}^9=923\cdot 2.0567650827103723E-27=1.898394171341674E-24$$