పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=756$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.010582010582010581$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=756$$

$$a_2=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{2-1}=756\cdot {0.010582010582010581}^1=756\cdot 0.010582010582010581=8$$

$$a_3=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{3-1}=756\cdot {0.010582010582010581}^2=756\cdot 0.00011197894795778393=0.08465608465608465$$

$$a_4=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{4-1}=756\cdot {0.010582010582010581}^3=756\cdot 1.1849624122516818E-06=0.0008958315836622714$$

$$a_5=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{5-1}=756\cdot {0.010582010582010581}^4=756\cdot 1.2539284785732081E-08=9.479699298013454E-06$$

$$a_6=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{6-1}=756\cdot {0.010582010582010581}^5=756\cdot 1.3269084429346117E-10=1.0031427828585665E-07$$

$$a_7=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{7-1}=756\cdot {0.010582010582010581}^6=756\cdot 1.4041359184493245E-12=1.0615267543476894E-09$$

$$a_8=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{8-1}=756\cdot {0.010582010582010581}^7=756\cdot 1.4858581147611898E-14=1.1233087347594594E-11$$

$$a_9=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{9-1}=756\cdot {0.010582010582010581}^8=756\cdot 1.5723366293769203E-16=1.1886864918089518E-13$$

$$a_{10}=a_1·r^{n-1}=756\cdot {0.010582010582010581}^{10-1}=756\cdot {0.010582010582010581}^9=756\cdot 1.663848285054942E-18=1.2578693035015362E-15$$