పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=45$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.044444444444444446$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=45$$

$$a_2=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{2-1}=45\cdot {0.044444444444444446}^1=45\cdot 0.044444444444444446=2$$

$$a_3=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{3-1}=45\cdot {0.044444444444444446}^2=45\cdot 0.0019753086419753087=0.08888888888888889$$

$$a_4=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{4-1}=45\cdot {0.044444444444444446}^3=45\cdot 8.779149519890262E-05=0.003950617283950618$$

$$a_5=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{5-1}=45\cdot {0.044444444444444446}^4=45\cdot 3.901844231062339E-06=0.00017558299039780524$$

$$a_6=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{6-1}=45\cdot {0.044444444444444446}^5=45\cdot 1.7341529915832618E-07=7.803688462124678E-06$$

$$a_7=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{7-1}=45\cdot {0.044444444444444446}^6=45\cdot 7.70734662925894E-09=3.468305983166523E-07$$

$$a_8=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{8-1}=45\cdot {0.044444444444444446}^7=45\cdot 3.425487390781752E-10=1.5414693258517884E-08$$

$$a_9=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{9-1}=45\cdot {0.044444444444444446}^8=45\cdot 1.5224388403474453E-11=6.850974781563504E-10$$

$$a_{10}=a_1·r^{n-1}=45\cdot {0.044444444444444446}^{10-1}=45\cdot {0.044444444444444446}^9=45\cdot 6.766394845988646E-13=3.0448776806948906E-11$$