పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=3,846$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.0013000520020800832$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=3846$$

$$a_2=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{2-1}=3846\cdot {0.0013000520020800832}^1=3846\cdot 0.0013000520020800832=5$$

$$a_3=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{3-1}=3846\cdot {0.0013000520020800832}^2=3846\cdot 1.6901352081124326E-06=0.006500260010400416$$

$$a_4=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{4-1}=3846\cdot {0.0013000520020800832}^3=3846\cdot 2.197263661092606E-09=8.450676040562163E-06$$

$$a_5=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{5-1}=3846\cdot {0.0013000520020800832}^4=3846\cdot 2.856557021701256E-12=1.098631830546303E-08$$

$$a_6=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{6-1}=3846\cdot {0.0013000520020800832}^5=3846\cdot 3.713672675118637E-15=1.428278510850628E-11$$

$$a_7=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{7-1}=3846\cdot {0.0013000520020800832}^6=3846\cdot 4.827967596358083E-18=1.8568363375593188E-14$$

$$a_8=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{8-1}=3846\cdot {0.0013000520020800832}^7=3846\cdot 6.276608939623092E-21=2.4139837981790414E-17$$

$$a_9=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{9-1}=3846\cdot {0.0013000520020800832}^8=3846\cdot 8.159918018230748E-24=3.138304469811546E-20$$

$$a_{10}=a_1·r^{n-1}=3846\cdot {0.0013000520020800832}^{10-1}=3846\cdot {0.0013000520020800832}^9=3846\cdot 1.060831775641023E-26=4.079959009115374E-23$$