పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=2,835$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.010582010582010581$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=2835$$

$$a_2=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{2-1}=2835\cdot {0.010582010582010581}^1=2835\cdot 0.010582010582010581=30$$

$$a_3=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{3-1}=2835\cdot {0.010582010582010581}^2=2835\cdot 0.00011197894795778393=0.31746031746031744$$

$$a_4=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{4-1}=2835\cdot {0.010582010582010581}^3=2835\cdot 1.1849624122516818E-06=0.003359368438733518$$

$$a_5=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{5-1}=2835\cdot {0.010582010582010581}^4=2835\cdot 1.2539284785732081E-08=3.554887236755045E-05$$

$$a_6=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{6-1}=2835\cdot {0.010582010582010581}^5=2835\cdot 1.3269084429346117E-10=3.761785435719624E-07$$

$$a_7=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{7-1}=2835\cdot {0.010582010582010581}^6=2835\cdot 1.4041359184493245E-12=3.980725328803835E-09$$

$$a_8=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{8-1}=2835\cdot {0.010582010582010581}^7=2835\cdot 1.4858581147611898E-14=4.212407755347973E-11$$

$$a_9=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{9-1}=2835\cdot {0.010582010582010581}^8=2835\cdot 1.5723366293769203E-16=4.457574344283569E-13$$

$$a_{10}=a_1·r^{n-1}=2835\cdot {0.010582010582010581}^{10-1}=2835\cdot {0.010582010582010581}^9=2835\cdot 1.663848285054942E-18=4.717009888130761E-15$$