పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=27$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1.1481481481481481$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=27$$

$$a_2=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{2-1}=27\cdot {1.1481481481481481}^1=27\cdot 1.1481481481481481=31$$

$$a_3=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{3-1}=27\cdot {1.1481481481481481}^2=27\cdot 1.318244170096022=35.59259259259259$$

$$a_4=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{4-1}=27\cdot {1.1481481481481481}^3=27\cdot 1.51353960270284=40.86556927297668$$

$$a_5=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{5-1}=27\cdot {1.1481481481481481}^4=27\cdot 1.7377676919921496=46.91972768378804$$

$$a_6=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{6-1}=27\cdot {1.1481481481481481}^5=27\cdot 1.9952147574724681=53.87079845175664$$

$$a_7=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{7-1}=27\cdot {1.1481481481481481}^6=27\cdot 2.2908021289498706=61.851657481646505$$

$$a_8=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{8-1}=27\cdot {1.1481481481481481}^7=27\cdot 2.6301802221276294=71.014865997446$$

$$a_9=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{9-1}=27\cdot {1.1481481481481481}^8=27\cdot 3.0198365513317227=81.53558688595652$$

$$a_{10}=a_1·r^{n-1}=27\cdot {1.1481481481481481}^{10-1}=27\cdot {1.1481481481481481}^9=27\cdot 3.4672197441216075=93.6149330912834$$