పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=27$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.8148148148148148$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=27$$

$$a_2=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{2-1}=27\cdot {0.8148148148148148}^1=27\cdot 0.8148148148148148=22$$

$$a_3=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{3-1}=27\cdot {0.8148148148148148}^2=27\cdot 0.6639231824417009=17.925925925925924$$

$$a_4=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{4-1}=27\cdot {0.8148148148148148}^3=27\cdot 0.540974444952497=14.606310013717419$$

$$a_5=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{5-1}=27\cdot {0.8148148148148148}^4=27\cdot 0.44079399218351606=11.901437788954933$$

$$a_6=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{6-1}=27\cdot {0.8148148148148148}^5=27\cdot 0.3591654751124945=9.697467828037352$$

$$a_7=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{7-1}=27\cdot {0.8148148148148148}^6=27\cdot 0.2926533500916622=7.901640452474879$$

$$a_8=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{8-1}=27\cdot {0.8148148148148148}^7=27\cdot 0.2384582852598729=6.438373702016568$$

$$a_9=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{9-1}=27\cdot {0.8148148148148148}^8=27\cdot 0.1942993435450816=5.246082275717203$$

$$a_{10}=a_1·r^{n-1}=27\cdot {0.8148148148148148}^{10-1}=27\cdot {0.8148148148148148}^9=27\cdot 0.15831798362932573=4.274585557991794$$