పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=2,550$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.00980392156862745$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=2550$$

$$a_2=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{2-1}=2550\cdot {0.00980392156862745}^1=2550\cdot 0.00980392156862745=25$$

$$a_3=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{3-1}=2550\cdot {0.00980392156862745}^2=2550\cdot 9.611687812379854E-05=0.2450980392156863$$

$$a_4=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{4-1}=2550\cdot {0.00980392156862745}^3=2550\cdot 9.423223345470445E-07=0.0024029219530949633$$

$$a_5=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{5-1}=2550\cdot {0.00980392156862745}^4=2550\cdot 9.238454260265142E-09=2.3558058363676112E-05$$

$$a_6=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{6-1}=2550\cdot {0.00980392156862745}^5=2550\cdot 9.057308098299158E-11=2.3096135650662853E-07$$

$$a_7=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{7-1}=2550\cdot {0.00980392156862745}^6=2550\cdot 8.879713821861919E-13=2.2643270245747895E-09$$

$$a_8=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{8-1}=2550\cdot {0.00980392156862745}^7=2550\cdot 8.705601786139136E-15=2.2199284554654798E-11$$

$$a_9=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{9-1}=2550\cdot {0.00980392156862745}^8=2550\cdot 8.534903711901114E-17=2.1764004465347843E-13$$

$$a_{10}=a_1·r^{n-1}=2550\cdot {0.00980392156862745}^{10-1}=2550\cdot {0.00980392156862745}^9=2550\cdot 8.367552658726583E-19=2.1337259279752784E-15$$