పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=10,00,000$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1E-06$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=1000000$$

$$a_2=a_1·r^{n-1}=1000000\cdot 1E-{06}^{2-1}=1000000\cdot 1E-{06}^1=1000000\cdot 1E-06=1$$

$$a_3=a_1·r^{n-1}=1000000\cdot 1E-{06}^{3-1}=1000000\cdot 1E-{06}^2=1000000\cdot 1E-12=1E-06$$

$$a_4=a_1·r^{n-1}=1000000\cdot 1E-{06}^{4-1}=1000000\cdot 1E-{06}^3=1000000\cdot 9.999999999999999E-19=1E-12$$

$$a_5=a_1·r^{n-1}=1000000\cdot 1E-{06}^{5-1}=1000000\cdot 1E-{06}^4=1000000\cdot 9.999999999999997E-25=9.999999999999997E-19$$

$$a_6=a_1·r^{n-1}=1000000\cdot 1E-{06}^{6-1}=1000000\cdot 1E-{06}^5=1000000\cdot 9.999999999999997E-31=9.999999999999997E-25$$

$$a_7=a_1·r^{n-1}=1000000\cdot 1E-{06}^{7-1}=1000000\cdot 1E-{06}^6=1000000\cdot 9.999999999999998E-37=9.999999999999997E-31$$

$$a_8=a_1·r^{n-1}=1000000\cdot 1E-{06}^{8-1}=1000000\cdot 1E-{06}^7=1000000\cdot 9.999999999999997E-43=9.999999999999998E-37$$

$$a_9=a_1·r^{n-1}=1000000\cdot 1E-{06}^{9-1}=1000000\cdot 1E-{06}^8=1000000\cdot 9.999999999999997E-49=9.999999999999997E-43$$

$$a_{10}=a_1·r^{n-1}=1000000\cdot 1E-{06}^{10-1}=1000000\cdot 1E-{06}^9=1000000\cdot 9.999999999999996E-55=9.999999999999997E-49$$