పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=91$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.08791208791208792$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=91$$

$$a_2=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{2-1}=91\cdot {0.08791208791208792}^1=91\cdot 0.08791208791208792=8$$

$$a_3=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{3-1}=91\cdot {0.08791208791208792}^2=91\cdot 0.007728535201062675=0.7032967032967035$$

$$a_4=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{4-1}=91\cdot {0.08791208791208792}^3=91\cdot 0.0006794316660274879=0.0618282816085014$$

$$a_5=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{5-1}=91\cdot {0.08791208791208792}^4=91\cdot 5.973025635406488E-05=0.005435453328219904$$

$$a_6=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{6-1}=91\cdot {0.08791208791208792}^5=91\cdot 5.2510115476101E-06=0.0004778420508325191$$

$$a_7=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{7-1}=91\cdot {0.08791208791208792}^6=91\cdot 4.616273888008879E-07=4.20080923808808E-05$$

$$a_8=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{8-1}=91\cdot {0.08791208791208792}^7=91\cdot 4.0582627586891246E-08=3.6930191104071032E-06$$

$$a_9=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{9-1}=91\cdot {0.08791208791208792}^8=91\cdot 3.567703524122308E-09=3.2466102069513E-07$$

$$a_{10}=a_1·r^{n-1}=91\cdot {0.08791208791208792}^{10-1}=91\cdot {0.08791208791208792}^9=91\cdot 3.136442658569062E-10=2.8541628192978466E-08$$