పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=90$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.9888888888888889$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=90$$

$$a_2=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{2-1}=90\cdot {0.9888888888888889}^1=90\cdot 0.9888888888888889=89$$

$$a_3=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{3-1}=90\cdot {0.9888888888888889}^2=90\cdot 0.9779012345679013=88.01111111111112$$

$$a_4=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{4-1}=90\cdot {0.9888888888888889}^3=90\cdot 0.9670356652949247=87.03320987654322$$

$$a_5=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{5-1}=90\cdot {0.9888888888888889}^4=90\cdot 0.9562908245694255=86.0661742112483$$

$$a_6=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{6-1}=90\cdot {0.9888888888888889}^5=90\cdot 0.9456653709630987=85.10988338667887$$

$$a_7=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{7-1}=90\cdot {0.9888888888888889}^6=90\cdot 0.9351579779523975=84.16421801571578$$

$$a_8=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{8-1}=90\cdot {0.9888888888888889}^7=90\cdot 0.9247673337529265=83.22906003776339$$

$$a_9=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{9-1}=90\cdot {0.9888888888888889}^8=90\cdot 0.9144921411556718=82.30429270401046$$

$$a_{10}=a_1·r^{n-1}=90\cdot {0.9888888888888889}^{10-1}=90\cdot {0.9888888888888889}^9=90\cdot 0.9043311173650533=81.3898005628548$$