పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=90$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.08888888888888889$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=90$$

$$a_2=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{2-1}=90\cdot {0.08888888888888889}^1=90\cdot 0.08888888888888889=8$$

$$a_3=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{3-1}=90\cdot {0.08888888888888889}^2=90\cdot 0.007901234567901235=0.7111111111111111$$

$$a_4=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{4-1}=90\cdot {0.08888888888888889}^3=90\cdot 0.000702331961591221=0.06320987654320989$$

$$a_5=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{5-1}=90\cdot {0.08888888888888889}^4=90\cdot 6.242950769699742E-05=0.005618655692729768$$

$$a_6=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{6-1}=90\cdot {0.08888888888888889}^5=90\cdot 5.549289573066438E-06=0.0004994360615759794$$

$$a_7=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{7-1}=90\cdot {0.08888888888888889}^6=90\cdot 4.932701842725722E-07=4.4394316584531494E-05$$

$$a_8=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{8-1}=90\cdot {0.08888888888888889}^7=90\cdot 4.3846238602006423E-08=3.946161474180578E-06$$

$$a_9=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{9-1}=90\cdot {0.08888888888888889}^8=90\cdot 3.89744343128946E-09=3.507699088160514E-07$$

$$a_{10}=a_1·r^{n-1}=90\cdot {0.08888888888888889}^{10-1}=90\cdot {0.08888888888888889}^9=90\cdot 3.4643941611461866E-10=3.117954745031568E-08$$