పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=90$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.14444444444444443$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=90$$

$$a_2=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{2-1}=90\cdot {0.14444444444444443}^1=90\cdot 0.14444444444444443=12.999999999999998$$

$$a_3=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{3-1}=90\cdot {0.14444444444444443}^2=90\cdot 0.020864197530864194=1.8777777777777775$$

$$a_4=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{4-1}=90\cdot {0.14444444444444443}^3=90\cdot 0.0030137174211248277=0.2712345679012345$$

$$a_5=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{5-1}=90\cdot {0.14444444444444443}^4=90\cdot 0.0004353147386069195=0.03917832647462276$$

$$a_6=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{6-1}=90\cdot {0.14444444444444443}^5=90\cdot 6.287879557655504E-05=0.0056590916018899535$$

$$a_7=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{7-1}=90\cdot {0.14444444444444443}^6=90\cdot 9.082492694391282E-06=0.0008174243424952154$$

$$a_8=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{8-1}=90\cdot {0.14444444444444443}^7=90\cdot 1.311915611412074E-06=0.00011807240502708666$$

$$a_9=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{9-1}=90\cdot {0.14444444444444443}^8=90\cdot 1.8949892164841066E-07=1.705490294835696E-05$$

$$a_{10}=a_1·r^{n-1}=90\cdot {0.14444444444444443}^{10-1}=90\cdot {0.14444444444444443}^9=90\cdot 2.737206646032598E-08=2.463485981429338E-06$$