పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=90$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1.2444444444444445$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=90$$

$$a_2=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{2-1}=90\cdot {1.2444444444444445}^1=90\cdot 1.2444444444444445=112$$

$$a_3=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{3-1}=90\cdot {1.2444444444444445}^2=90\cdot 1.548641975308642=139.3777777777778$$

$$a_4=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{4-1}=90\cdot {1.2444444444444445}^3=90\cdot 1.92719890260631=173.44790123456792$$

$$a_5=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{5-1}=90\cdot {1.2444444444444445}^4=90\cdot 2.3982919676878525=215.84627709190673$$

$$a_6=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{6-1}=90\cdot {1.2444444444444445}^5=90\cdot 2.984541115344883=268.60870038103945$$

$$a_7=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{7-1}=90\cdot {1.2444444444444445}^6=90\cdot 3.7140956102069658=334.2686049186269$$

$$a_8=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{8-1}=90\cdot {1.2444444444444445}^7=90\cdot 4.621985648257557=415.9787083431802$$

$$a_9=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{9-1}=90\cdot {1.2444444444444445}^8=90\cdot 5.751804362276072=517.6623926048464$$

$$a_{10}=a_1·r^{n-1}=90\cdot {1.2444444444444445}^{10-1}=90\cdot {1.2444444444444445}^9=90\cdot 7.157800984165778=644.20208857492$$