పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=88$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.7272727272727273$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=88$$

$$a_2=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{2-1}=88\cdot {0.7272727272727273}^1=88\cdot 0.7272727272727273=64$$

$$a_3=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{3-1}=88\cdot {0.7272727272727273}^2=88\cdot 0.5289256198347108=46.54545454545455$$

$$a_4=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{4-1}=88\cdot {0.7272727272727273}^3=88\cdot 0.38467317806160783=33.85123966942149$$

$$a_5=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{5-1}=88\cdot {0.7272727272727273}^4=88\cdot 0.279762311317533=24.6190833959429$$

$$a_6=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{6-1}=88\cdot {0.7272727272727273}^5=88\cdot 0.20346349914002398=17.90478792432211$$

$$a_7=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{7-1}=88\cdot {0.7272727272727273}^6=88\cdot 0.14797345392001746=13.021663944961537$$

$$a_8=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{8-1}=88\cdot {0.7272727272727273}^7=88\cdot 0.10761705739637634=9.470301050881117$$

$$a_9=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{9-1}=88\cdot {0.7272727272727273}^8=88\cdot 0.07826695083372824=6.8874916733680855$$

$$a_{10}=a_1·r^{n-1}=88\cdot {0.7272727272727273}^{10-1}=88\cdot {0.7272727272727273}^9=88\cdot 0.056921418788166=5.009084853358608$$