పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=88$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.22727272727272727$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=88$$

$$a_2=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{2-1}=88\cdot {0.22727272727272727}^1=88\cdot 0.22727272727272727=20$$

$$a_3=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{3-1}=88\cdot {0.22727272727272727}^2=88\cdot 0.051652892561983466=4.545454545454545$$

$$a_4=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{4-1}=88\cdot {0.22727272727272727}^3=88\cdot 0.01173929376408715=1.0330578512396693$$

$$a_5=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{5-1}=88\cdot {0.22727272727272727}^4=88\cdot 0.002668021310019807=0.23478587528174302$$

$$a_6=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{6-1}=88\cdot {0.22727272727272727}^5=88\cdot 0.0006063684795499561=0.05336042620039613$$

$$a_7=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{7-1}=88\cdot {0.22727272727272727}^6=88\cdot 0.00013781101807953548=0.012127369590999122$$

$$a_8=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{8-1}=88\cdot {0.22727272727272727}^7=88\cdot 3.1320685927167155E-05=0.00275622036159071$$

$$a_9=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{9-1}=88\cdot {0.22727272727272727}^8=88\cdot 7.118337710719808E-06=0.000626413718543343$$

$$a_{10}=a_1·r^{n-1}=88\cdot {0.22727272727272727}^{10-1}=88\cdot {0.22727272727272727}^9=88\cdot 1.6178040251635924E-06=0.00014236675421439612$$