పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=6,020$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.0425249169435216$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=6020$$

$$a_2=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{2-1}=6020\cdot {0.0425249169435216}^1=6020\cdot 0.0425249169435216=256$$

$$a_3=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{3-1}=6020\cdot {0.0425249169435216}^2=6020\cdot 0.0018083685610534102=10.886378737541529$$

$$a_4=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{4-1}=6020\cdot {0.0425249169435216}^3=6020\cdot 7.690072286207193E-05=0.462942351629673$$

$$a_5=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{5-1}=6020\cdot {0.0425249169435216}^4=6020\cdot 3.270196852606381E-06=0.019686585052690414$$

$$a_6=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{6-1}=6020\cdot {0.0425249169435216}^5=6020\cdot 1.3906484954605211E-07=0.0008371703942672337$$

$$a_7=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{7-1}=6020\cdot {0.0425249169435216}^6=6020\cdot 5.913721176709193E-09=3.560060148378934E-05$$

$$a_8=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{8-1}=6020\cdot {0.0425249169435216}^7=6020\cdot 2.5148050186670324E-10=1.5139126212375535E-06$$

$$a_9=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{9-1}=6020\cdot {0.0425249169435216}^8=6020\cdot 1.0694187454796682E-11=6.437900847787603E-08$$

$$a_{10}=a_1·r^{n-1}=6020\cdot {0.0425249169435216}^{10-1}=6020\cdot {0.0425249169435216}^9=6020\cdot 4.547694332936795E-13=2.7377119884279507E-09$$