పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=51,425$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.01487603305785124$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=51425$$

$$a_2=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{2-1}=51425\cdot {0.01487603305785124}^1=51425\cdot 0.01487603305785124=765$$

$$a_3=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{3-1}=51425\cdot {0.01487603305785124}^2=51425\cdot 0.0002212963595382829=11.3801652892562$$

$$a_4=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{4-1}=51425\cdot {0.01487603305785124}^3=51425\cdot 3.29201196007363E-06=0.16929171504678645$$

$$a_5=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{5-1}=51425\cdot {0.01487603305785124}^4=51425\cdot 4.8972078744896975E-08=0.002518389149456327$$

$$a_6=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{6-1}=51425\cdot {0.01487603305785124}^5=51425\cdot 7.285102623207815E-10=3.746364023984619E-05$$

$$a_7=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{7-1}=51425\cdot {0.01487603305785124}^6=51425\cdot 1.0837342745267823E-11=5.573103506753978E-07$$

$$a_8=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{8-1}=51425\cdot {0.01487603305785124}^7=51425\cdot 1.6121666893786844E-13=8.290567200129884E-09$$

$$a_9=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{9-1}=51425\cdot {0.01487603305785124}^8=51425\cdot 2.3982644965963902E-15=1.2333075173746936E-10$$

$$a_{10}=a_1·r^{n-1}=51425\cdot {0.01487603305785124}^{10-1}=51425\cdot {0.01487603305785124}^9=51425\cdot 3.567666193283886E-17=1.8346723398962385E-12$$