పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=495$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.4444444444444444$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=495$$

$$a_2=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{2-1}=495\cdot {0.4444444444444444}^1=495\cdot 0.4444444444444444=220$$

$$a_3=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{3-1}=495\cdot {0.4444444444444444}^2=495\cdot 0.19753086419753085=97.77777777777777$$

$$a_4=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{4-1}=495\cdot {0.4444444444444444}^3=495\cdot 0.08779149519890259=43.45679012345678$$

$$a_5=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{5-1}=495\cdot {0.4444444444444444}^4=495\cdot 0.039018442310623375=19.314128943758572$$

$$a_6=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{6-1}=495\cdot {0.4444444444444444}^5=495\cdot 0.01734152991583261=8.584057308337142$$

$$a_7=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{7-1}=495\cdot {0.4444444444444444}^6=495\cdot 0.007707346629258937=3.815136581483174$$

$$a_8=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{8-1}=495\cdot {0.4444444444444444}^7=495\cdot 0.0034254873907817495=1.695616258436966$$

$$a_9=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{9-1}=495\cdot {0.4444444444444444}^8=495\cdot 0.001522438840347444=0.7536072259719848$$

$$a_{10}=a_1·r^{n-1}=495\cdot {0.4444444444444444}^{10-1}=495\cdot {0.4444444444444444}^9=495\cdot 0.000676639484598864=0.3349365448764377$$