పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=45$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.08888888888888889$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=45$$

$$a_2=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{2-1}=45\cdot {0.08888888888888889}^1=45\cdot 0.08888888888888889=4$$

$$a_3=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{3-1}=45\cdot {0.08888888888888889}^2=45\cdot 0.007901234567901235=0.35555555555555557$$

$$a_4=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{4-1}=45\cdot {0.08888888888888889}^3=45\cdot 0.000702331961591221=0.031604938271604946$$

$$a_5=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{5-1}=45\cdot {0.08888888888888889}^4=45\cdot 6.242950769699742E-05=0.002809327846364884$$

$$a_6=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{6-1}=45\cdot {0.08888888888888889}^5=45\cdot 5.549289573066438E-06=0.0002497180307879897$$

$$a_7=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{7-1}=45\cdot {0.08888888888888889}^6=45\cdot 4.932701842725722E-07=2.2197158292265747E-05$$

$$a_8=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{8-1}=45\cdot {0.08888888888888889}^7=45\cdot 4.3846238602006423E-08=1.973080737090289E-06$$

$$a_9=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{9-1}=45\cdot {0.08888888888888889}^8=45\cdot 3.89744343128946E-09=1.753849544080257E-07$$

$$a_{10}=a_1·r^{n-1}=45\cdot {0.08888888888888889}^{10-1}=45\cdot {0.08888888888888889}^9=45\cdot 3.4643941611461866E-10=1.558977372515784E-08$$