పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=429$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.046620046620046623$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=429$$

$$a_2=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{2-1}=429\cdot {0.046620046620046623}^1=429\cdot 0.046620046620046623=20$$

$$a_3=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{3-1}=429\cdot {0.046620046620046623}^2=429\cdot 0.0021734287468553205=0.9324009324009325$$

$$a_4=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{4-1}=429\cdot {0.046620046620046623}^3=429\cdot 0.00010132534950374456=0.043468574937106416$$

$$a_5=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{5-1}=429\cdot {0.046620046620046623}^4=429\cdot 4.7237925176570895E-06=0.0020265069900748914$$

$$a_6=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{6-1}=429\cdot {0.046620046620046623}^5=429\cdot 2.202234273966009E-07=9.447585035314179E-05$$

$$a_7=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{7-1}=429\cdot {0.046620046620046623}^6=429\cdot 1.0266826452055988E-08=4.404468547932019E-06$$

$$a_8=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{8-1}=429\cdot {0.046620046620046623}^7=429\cdot 4.78639927834778E-10=2.053365290411198E-07$$

$$a_9=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{9-1}=429\cdot {0.046620046620046623}^8=429\cdot 2.2314215749873103E-11=9.57279855669556E-09$$

$$a_{10}=a_1·r^{n-1}=429\cdot {0.046620046620046623}^{10-1}=429\cdot {0.046620046620046623}^9=429\cdot 1.0402897785488626E-12=4.4628431499746203E-10$$