పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=425$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.004705882352941176$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=425$$

$$a_2=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{2-1}=425\cdot {0.004705882352941176}^1=425\cdot 0.004705882352941176=1.9999999999999998$$

$$a_3=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{3-1}=425\cdot {0.004705882352941176}^2=425\cdot 2.214532871972318E-05=0.009411764705882352$$

$$a_4=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{4-1}=425\cdot {0.004705882352941176}^3=425\cdot 1.0421331162222672E-07=4.429065743944636E-05$$

$$a_5=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{5-1}=425\cdot {0.004705882352941176}^4=425\cdot 4.904155841045962E-10=2.0842662324445342E-07$$

$$a_6=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{6-1}=425\cdot {0.004705882352941176}^5=425\cdot 2.3078380428451588E-12=9.808311682091925E-10$$

$$a_7=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{7-1}=425\cdot {0.004705882352941176}^6=425\cdot 1.0860414319271334E-14=4.615676085690317E-12$$

$$a_8=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{8-1}=425\cdot {0.004705882352941176}^7=425\cdot 5.1107832090688625E-17=2.1720828638542665E-14$$

$$a_9=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{9-1}=425\cdot {0.004705882352941176}^8=425\cdot 2.4050744513265236E-19=1.0221566418137725E-16$$

$$a_{10}=a_1·r^{n-1}=425\cdot {0.004705882352941176}^{10-1}=425\cdot {0.004705882352941176}^9=425\cdot 1.1317997418007168E-21=4.810148902653046E-19$$