పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=33$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1.0606060606060606$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=33$$

$$a_2=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{2-1}=33\cdot {1.0606060606060606}^1=33\cdot 1.0606060606060606=35$$

$$a_3=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{3-1}=33\cdot {1.0606060606060606}^2=33\cdot 1.1248852157943066=37.12121212121212$$

$$a_4=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{4-1}=33\cdot {1.0606060606060606}^3=33\cdot 1.193060077357598=39.37098255280073$$

$$a_5=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{5-1}=33\cdot {1.0606060606060606}^4=33\cdot 1.2653667487126037=41.75710270751592$$

$$a_6=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{6-1}=33\cdot {1.0606060606060606}^5=33\cdot 1.3420556425739736=44.28783620494113$$

$$a_7=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{7-1}=33\cdot {1.0606060606060606}^6=33\cdot 1.4233923481845174=46.97194749008908$$

$$a_8=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{8-1}=33\cdot {1.0606060606060606}^7=33\cdot 1.509658551104791=49.81873218645811$$

$$a_9=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{9-1}=33\cdot {1.0606060606060606}^8=33\cdot 1.6011530087475057=52.83804928866768$$

$$a_{10}=a_1·r^{n-1}=33\cdot {1.0606060606060606}^{10-1}=33\cdot {1.0606060606060606}^9=33\cdot 1.698192585035233=56.04035530616269$$