పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=316$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.006329113924050633$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=316$$

$$a_2=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{2-1}=316\cdot {0.006329113924050633}^1=316\cdot 0.006329113924050633=2$$

$$a_3=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{3-1}=316\cdot {0.006329113924050633}^2=316\cdot 4.00576830636116E-05=0.012658227848101266$$

$$a_4=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{4-1}=316\cdot {0.006329113924050633}^3=316\cdot 2.535296396431114E-07=8.01153661272232E-05$$

$$a_5=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{5-1}=316\cdot {0.006329113924050633}^4=316\cdot 1.6046179724247555E-09=5.070592792862228E-07$$

$$a_6=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{6-1}=316\cdot {0.006329113924050633}^5=316\cdot 1.0155809952055415E-11=3.209235944849511E-09$$

$$a_7=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{7-1}=316\cdot {0.006329113924050633}^6=316\cdot 6.427727817756592E-14=2.031161990411083E-11$$

$$a_8=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{8-1}=316\cdot {0.006329113924050633}^7=316\cdot 4.068182163137083E-16=1.2855455635513183E-13$$

$$a_9=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{9-1}=316\cdot {0.006329113924050633}^8=316\cdot 2.5747988374285337E-18=8.136364326274166E-16$$

$$a_{10}=a_1·r^{n-1}=316\cdot {0.006329113924050633}^{10-1}=316\cdot {0.006329113924050633}^9=316\cdot 1.6296195173598315E-20=5.1495976748570674E-18$$