పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=27$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=2.4814814814814814$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=27$$

$$a_2=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{2-1}=27\cdot {2.4814814814814814}^1=27\cdot 2.4814814814814814=67$$

$$a_3=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{3-1}=27\cdot {2.4814814814814814}^2=27\cdot 6.157750342935528=166.25925925925927$$

$$a_4=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{4-1}=27\cdot {2.4814814814814814}^3=27\cdot 15.280343443580753=412.56927297668034$$

$$a_5=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{5-1}=27\cdot {2.4814814814814814}^4=27\cdot 37.91788928592261=1023.7830107199105$$

$$a_6=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{6-1}=27\cdot {2.4814814814814814}^5=27\cdot 94.09254007988203=2540.498582156815$$

$$a_7=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{7-1}=27\cdot {2.4814814814814814}^6=27\cdot 233.48889575378132=6304.200185352096$$

$$a_8=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{8-1}=27\cdot {2.4814814814814814}^7=27\cdot 579.3983709445685=15643.756015503348$$

$$a_9=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{9-1}=27\cdot {2.4814814814814814}^8=27\cdot 1437.7663278994846=38819.69085328608$$

$$a_{10}=a_1·r^{n-1}=27\cdot {2.4814814814814814}^{10-1}=27\cdot {2.4814814814814814}^9=27\cdot 3567.7905173802023=96330.34396926546$$