పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=27$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=2.4444444444444446$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=27$$

$$a_2=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{2-1}=27\cdot {2.4444444444444446}^1=27\cdot 2.4444444444444446=66$$

$$a_3=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{3-1}=27\cdot {2.4444444444444446}^2=27\cdot 5.975308641975309=161.33333333333334$$

$$a_4=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{4-1}=27\cdot {2.4444444444444446}^3=27\cdot 14.606310013717424=394.37037037037044$$

$$a_5=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{5-1}=27\cdot {2.4444444444444446}^4=27\cdot 35.70431336686482=964.0164609053501$$

$$a_6=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{6-1}=27\cdot {2.4444444444444446}^5=27\cdot 87.27721045233623=2356.4846822130785$$

$$a_7=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{7-1}=27\cdot {2.4444444444444446}^6=27\cdot 213.3442922168219=5760.295889854192$$

$$a_8=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{8-1}=27\cdot {2.4444444444444446}^7=27\cdot 521.5082698633425=14080.723286310249$$

$$a_9=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{9-1}=27\cdot {2.4444444444444446}^8=27\cdot 1274.7979929992819=34419.54581098061$$

$$a_{10}=a_1·r^{n-1}=27\cdot {2.4444444444444446}^{10-1}=27\cdot {2.4444444444444446}^9=27\cdot 3116.1728717760225=84136.66753795261$$