పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=27$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.14814814814814814$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=27$$

$$a_2=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{2-1}=27\cdot {0.14814814814814814}^1=27\cdot 0.14814814814814814=4$$

$$a_3=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{3-1}=27\cdot {0.14814814814814814}^2=27\cdot 0.02194787379972565=0.5925925925925926$$

$$a_4=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{4-1}=27\cdot {0.14814814814814814}^3=27\cdot 0.0032515368592186144=0.08779149519890259$$

$$a_5=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{5-1}=27\cdot {0.14814814814814814}^4=27\cdot 0.0004817091643286836=0.013006147436874458$$

$$a_6=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{6-1}=27\cdot {0.14814814814814814}^5=27\cdot 7.136432064128646E-05=0.0019268366573147345$$

$$a_7=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{7-1}=27\cdot {0.14814814814814814}^6=27\cdot 1.0572491946857252E-05=0.0002854572825651458$$

$$a_8=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{8-1}=27\cdot {0.14814814814814814}^7=27\cdot 1.5662951032381114E-06=4.228996778742901E-05$$

$$a_9=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{9-1}=27\cdot {0.14814814814814814}^8=27\cdot 2.320437189982387E-07=6.265180412952445E-06$$

$$a_{10}=a_1·r^{n-1}=27\cdot {0.14814814814814814}^{10-1}=27\cdot {0.14814814814814814}^9=27\cdot 3.437684725899833E-08=9.281748759929549E-07$$