పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=225$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1.3244444444444445$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=225$$

$$a_2=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{2-1}=225\cdot {1.3244444444444445}^1=225\cdot 1.3244444444444445=298$$

$$a_3=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{3-1}=225\cdot {1.3244444444444445}^2=225\cdot 1.7541530864197534=394.6844444444445$$

$$a_4=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{4-1}=225\cdot {1.3244444444444445}^3=225\cdot 2.323278310013718=522.7376197530865$$

$$a_5=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{5-1}=225\cdot {1.3244444444444445}^4=225\cdot 3.077053050595947=692.3369363840881$$

$$a_6=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{6-1}=225\cdot {1.3244444444444445}^5=225\cdot 4.075385818122632=916.9618090775921$$

$$a_7=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{7-1}=225\cdot {1.3244444444444445}^6=225\cdot 5.397622105780197=1214.4649738005444$$

$$a_8=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{8-1}=225\cdot {1.3244444444444445}^7=225\cdot 7.148850611211106=1608.4913875224988$$

$$a_9=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{9-1}=225\cdot {1.3244444444444445}^8=225\cdot 9.46825547618182=2130.3574821409097$$

$$a_{10}=a_1·r^{n-1}=225\cdot {1.3244444444444445}^{10-1}=225\cdot {1.3244444444444445}^9=225\cdot 12.540178364009702=2821.540131902183$$