పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=162$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.14814814814814814$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=162$$

$$a_2=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{2-1}=162\cdot {0.14814814814814814}^1=162\cdot 0.14814814814814814=24$$

$$a_3=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{3-1}=162\cdot {0.14814814814814814}^2=162\cdot 0.02194787379972565=3.5555555555555554$$

$$a_4=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{4-1}=162\cdot {0.14814814814814814}^3=162\cdot 0.0032515368592186144=0.5267489711934156$$

$$a_5=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{5-1}=162\cdot {0.14814814814814814}^4=162\cdot 0.0004817091643286836=0.07803688462124675$$

$$a_6=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{6-1}=162\cdot {0.14814814814814814}^5=162\cdot 7.136432064128646E-05=0.011561019943888407$$

$$a_7=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{7-1}=162\cdot {0.14814814814814814}^6=162\cdot 1.0572491946857252E-05=0.0017127436953908747$$

$$a_8=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{8-1}=162\cdot {0.14814814814814814}^7=162\cdot 1.5662951032381114E-06=0.00025373980672457403$$

$$a_9=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{9-1}=162\cdot {0.14814814814814814}^8=162\cdot 2.320437189982387E-07=3.759108247771467E-05$$

$$a_{10}=a_1·r^{n-1}=162\cdot {0.14814814814814814}^{10-1}=162\cdot {0.14814814814814814}^9=162\cdot 3.437684725899833E-08=5.569049255957729E-06$$