పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=1,242$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.018518518518518517$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=1242$$

$$a_2=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{2-1}=1242\cdot {0.018518518518518517}^1=1242\cdot 0.018518518518518517=23$$

$$a_3=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{3-1}=1242\cdot {0.018518518518518517}^2=1242\cdot 0.0003429355281207133=0.4259259259259259$$

$$a_4=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{4-1}=1242\cdot {0.018518518518518517}^3=1242\cdot 6.350657928161356E-06=0.007887517146776404$$

$$a_5=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{5-1}=1242\cdot {0.018518518518518517}^4=1242\cdot 1.1760477644743252E-07=0.0001460651323477112$$

$$a_6=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{6-1}=1242\cdot {0.018518518518518517}^5=1242\cdot 2.1778662305080097E-09=2.704909858290948E-06$$

$$a_7=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{7-1}=1242\cdot {0.018518518518518517}^6=1242\cdot 4.033085612051869E-11=5.009092330168421E-08$$

$$a_8=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{8-1}=1242\cdot {0.018518518518518517}^7=1242\cdot 7.468677059355313E-13=9.276096907719299E-10$$

$$a_9=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{9-1}=1242\cdot {0.018518518518518517}^8=1242\cdot 1.3830883443250578E-14=1.717795723651722E-11$$

$$a_{10}=a_1·r^{n-1}=1242\cdot {0.018518518518518517}^{10-1}=1242\cdot {0.018518518518518517}^9=1242\cdot 2.5612747117130703E-16=3.1811031919476334E-13$$