పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=1,224$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1.4444444444444444$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=1224$$

$$a_2=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{2-1}=1224\cdot {1.4444444444444444}^1=1224\cdot 1.4444444444444444=1768$$

$$a_3=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{3-1}=1224\cdot {1.4444444444444444}^2=1224\cdot 2.0864197530864197=2553.777777777778$$

$$a_4=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{4-1}=1224\cdot {1.4444444444444444}^3=1224\cdot 3.0137174211248285=3688.7901234567903$$

$$a_5=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{5-1}=1224\cdot {1.4444444444444444}^4=1224\cdot 4.353147386069196=5328.252400548696$$

$$a_6=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{6-1}=1224\cdot {1.4444444444444444}^5=1224\cdot 6.287879557655506=7696.364578570339$$

$$a_7=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{7-1}=1224\cdot {1.4444444444444444}^6=1224\cdot 9.082492694391286=11116.971057934934$$

$$a_8=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{8-1}=1224\cdot {1.4444444444444444}^7=1224\cdot 13.119156114120747=16057.847083683795$$

$$a_9=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{9-1}=1224\cdot {1.4444444444444444}^8=1224\cdot 18.949892164841078=23194.66800976548$$

$$a_{10}=a_1·r^{n-1}=1224\cdot {1.4444444444444444}^{10-1}=1224\cdot {1.4444444444444444}^9=1224\cdot 27.372066460326=33503.409347439025$$