పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(DB\right)}_{16}=13\cdot {16}^1+11\cdot {16}^0$$

$$13\cdot {16}^1+11\cdot {16}^0=219$$

$$\frac{219}{10}=21rema\in der9$$

$$\frac{21}{10}=2rema\in der1$$

$$\frac{2}{10}=0rema\in der2$$

$$9\to 1\to 2=219$$

$$219\left(base10\right)={\left(219\right)}_{10}$$