పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(CEF\right)}_{16}=12\cdot {16}^2+14\cdot {16}^1+15\cdot {16}^0$$

$$12\cdot {16}^2+14\cdot {16}^1+15\cdot {16}^0=3311$$

$$\frac{3311}{10}=331rema\in der1$$

$$\frac{331}{10}=33rema\in der1$$

$$\frac{33}{10}=3rema\in der3$$

$$\frac{3}{10}=0rema\in der3$$

$$1\to 1\to 3\to 3=3311$$

$$3311\left(base10\right)={\left(3311\right)}_{10}$$