పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(CED\right)}_{16}=12\cdot {16}^2+14\cdot {16}^1+13\cdot {16}^0$$

$$12\cdot {16}^2+14\cdot {16}^1+13\cdot {16}^0=3309$$

$$\frac{3309}{10}=330rema\in der9$$

$$\frac{330}{10}=33rema\in der0$$

$$\frac{33}{10}=3rema\in der3$$

$$\frac{3}{10}=0rema\in der3$$

$$9\to 0\to 3\to 3=3309$$

$$3309\left(base10\right)={\left(3309\right)}_{10}$$